Solve the following two equations: 1) 7a-4<=17 and 2) 3/4x+5>-15
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1) 7a-4<=17

Add 4 to each side:

7a <= 21

Divide each side by 7:

a <=... Attachments
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Add 4 to each side:

7a <= 21

Divide each side by 7:

a <=... Attachments

a <= 21/7

that is a <= 3.

2) 3/4x+5>-15

subtracting 5 from both sides gives

3/4x > -20

multiply both sides by 4, to obtain

3x > -80

Finally dividing Attachments
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that is a <= 3.

2) 3/4x+5>-15

subtracting 5 from both sides gives

3/4x > -20

multiply both sides by 4, to obtain

3x > -80

Finally dividing Attachments